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IGCSE · Cambridge (CIE) · 0610

Interpret a stated binary-fission population model

Calculate doubling counts and interval averages without assigning universal generation times.

Asexual reproduction pathway · 16.1

Core and Extended; Biology 0610, 2026–2028. Use the stated specimen features and evidence. Diagrams are schematic. Written practice is self-checked

Before you begin

  • Recall cells, DNA, inherited characteristics and the distinction between growth of an organism and production of offspring.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

What happens after one complete model interval?

What you will learn

  • Track completed divisions and totals
  • Distinguish net increase from final count

Interpret a stated binary-fission population model

Invented totals 4, 8, 16, 32, 64 at 0, 40, 80, 120, 160 min. Net increase 60; full-interval mean 0.375 cells/min. No death or migration in this model.Stated counts after model intervals01632486404080120160Time / min · vertical axis = cells
Invented totals 4, 8, 16, 32, 64 at 0, 40, 80, 120, 160 min. Net increase 60; full-interval mean 0.375 cells/min. No death or migration in this model. Original teaching model. Points are supplied observations; dashed joins guide the eye, rather than proving counts between observations.
Invented no-death bacterial counts — completed 40-minute intervals
Time / minTotal cells
0 min4
40 min8
80 min16
120 min32
160 min64
Asexual reproduction model reference
FeatureMeaning
Interval40 min only in the supplied model
Four doublings4 × 2⁴ = 64 cells
Net increase64 − 4 = 60 cells
LimitNo universal generation time or indefinite-growth claim

Track completed divisions and totals

The invented count model starts with four bacterial cells. Every cell completes one binary fission during each stated 40-minute interval, with no death or movement into or out of the group. Each original becomes two daughters, so the total doubles rather than increasing by a constant four. Totals at 0, 40, 80, 120 and 160 minutes are 4, 8, 16, 32 and 64.

Four completed doubling intervals take 160 minutes and give 4 × 2⁴ = 64 cells. Net increase is 64 − 4 = 60 cells, distinct from final total. The full-interval mean net increase is 60/160 = 0.375 cells per minute. Use net change in the numerator when a rate of increase is requested, and retain the time unit from the supplied record.

Distinguish net increase from final count

The successive 40-minute increases are 4, 8, 16 and 32 cells. Their interval-average rates are 0.1, 0.2, 0.4 and 0.8 cells per minute. Thus the model does not have a constant absolute growth rate even though the doubling interval is fixed. A constant multiplication factor and a constant added count are different patterns; check the differences before describing a graph.

These clean data illustrate reproduction and counting rather than a universal bacterial growth rule. Real populations depend on species, nutrients, temperature, space, death and other conditions. No pathogen culture is assigned. Use the stated assumptions and time intervals; do not extend unrestricted doubling indefinitely or treat the model as a clinical threshold.

Pause and explain

What is the net increase from 4 to 64?

Put the idea to work

Worked example

Four bacteria undergo three complete doublings with no death. Find total and net increase.

Show the worked solution
  1. 4→8→16→32.
  2. Subtract the starting four.

Answer 32 cells in total; net increase 28 cells.

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

Find the total after four completed doublings from four cells.

Give me a hint

Apply four factors of two.

Compare my reasoning
  1. 4→8→16→32→64.
  2. Do not add unchanged parents.

64 cells.

Look for these in your work

  • Use four doublings
  • Count daughters without extra parents
2 · Independent

Calculate the full-interval mean net increase per minute over 160 minutes.

Give me a hint

Subtract initial count before dividing.

Compare my reasoning
  1. 64−4 = 60 cells.
  2. 60/160 = 0.375 cells/min.

0.375 cells/min, using the net increase of 60 cells.

Look for these in your work

  • Use net change
  • Retain rate units
3 · Transfer

Does this prove constant absolute growth or a universal bacterial 40-minute generation time?

Give me a hint

Compare added counts and retain assumptions.

Compare my reasoning
  1. The added counts rise: 4, 8, 16 and 32.
  2. The time interval is stipulated for this model.

No. Absolute interval rates increase as the population doubles, and the stated 40-minute interval is not a universal bacterial generation time.

Look for these in your work

  • Distinguish factors and differences
  • State model limits

Common mistakes

  • Adding four after every interval.
  • Using final total as net increase.
Recall without your notes

What can you explain now?

What is the net increase from 4 to 64?

Compare with the explanation

60 cells

Subtract initial from final.

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Make it stick

Calculate a doubling total and net increase, then distinguish a constant factor from a constant added count.

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Biology

Course scope and assessment

780 sequenced lessons provide 2340 guided, independent and application problems in characteristics, classification, cells, organisation, specimen size, membrane transport, biological molecules, enzymes, plant and human nutrition, plant transport, circulatory systems, the heart, blood vessels, blood, disease transmission, body defences, immunity, gas exchange in humans, respiration energy uses and investigations, aerobic respiration, anaerobic respiration and recovery, excretion in humans, coordination and response, sense organs, hormones, homeostasis, tropic responses, drugs, asexual reproduction, sexual reproduction, sexual reproduction in plants, sexual reproduction in humans, sex hormones in humans, sexually transmitted infections, chromosomes, genes and proteins, mitosis, meiosis, monohybrid inheritance, variation, adaptive features, selection, energy flow, food chains and webs, nutrient cycles, population, community, ecosystem, population-growth phases, food supply, habitat destruction, pollution, conservation, biotechnology and genetic modification. 61 of 61 syllabus sections have linked teaching and staged practice. The earlier inheritance overview remains introductory, and the monohybrid pathway develops the relevant Core and Supplement requirements. This is not full programme completion or guaranteed exam readiness. Written practice is self-checked.

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