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A Level · Cambridge (CIE) · 9701

Balance and calculate permanganate redox reactions

Balance acidified permanganate reactions with iron(II) or ethanedioate and use the stoichiometric ratios in calculations.

Chemistry of transition elements · Cambridge International AS & A Level Chemistry 9701 · 28.2

A Level; Cambridge International Chemistry 9701, 2028–2030 syllabus, Topic 28. Use the first-row transition elements titanium to copper and the species explicitly named in the syllabus. Where redox potentials or stability constants are needed, use the values supplied in the question. Colour descriptions can depend on conditions and concentration. Written practice is self-checked

Before you begin

  • Use electron configurations, oxidation numbers, ionic equations, equilibrium expressions and the AS redox and bonding models.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

In acidified permanganate/Fe²⁺, what is the mole ratio MnO₄⁻:Fe²⁺?

What you will learn

  • Balance MnO₄⁻/Fe²⁺ in acid
  • Balance MnO₄⁻/C₂O₄²⁻ in acid
  • Use mole ratios and supplied concentrations or volumes in calculations

Permanganate oxidises iron(II) in acid

In acidic solution, MnO₄⁻ is reduced to Mn²⁺. Fe²⁺ is oxidised to Fe³⁺. Combining the half-equations gives MnO₄⁻ + 8H⁺ + 5Fe²⁺ → Mn²⁺ + 4H₂O + 5Fe³⁺.

The mole ratio is 1 mol MnO₄⁻ to 5 mol Fe²⁺. Use the balanced equation only for the specified acidic conditions; changing the medium may change the manganese product.

Permanganate oxidises ethanedioate to carbon dioxide

In acid, C₂O₄²⁻ is oxidised to CO₂ and MnO₄⁻ is reduced to Mn²⁺: 2MnO₄⁻ + 16H⁺ + 5C₂O₄²⁻ → 2Mn²⁺ + 8H₂O + 10CO₂.

The mole ratio is 2 mol MnO₄⁻ to 5 mol C₂O₄²⁻. In a calculation, convert each measured concentration and volume to moles, use the ratio, then calculate the requested amount or concentration. These are written-equation exercises, not instructions to carry out a reaction.

Pause and explain

What is the carbon product when ethanedioate is oxidised by acidified permanganate?

Put the idea to work

Worked example

25.0 cm³ of 0.0200 mol dm⁻³ Fe²⁺ reacts exactly with acidified MnO₄⁻. Calculate the volume of 0.0100 mol dm⁻³ MnO₄⁻ required.

Show the worked solution
  1. Find n(Fe²⁺) = 0.0200 × 0.0250.
  2. Use 1 MnO₄⁻ : 5 Fe²⁺.
  3. Divide permanganate moles by its concentration.

Answer n(Fe²⁺) = 5.00 × 10⁻⁴ mol, so n(MnO₄⁻) = 1.00 × 10⁻⁴ mol. V = n/c = 0.0100 dm³ = 10.0 cm³.

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

Calculate moles of Fe²⁺ in 20.0 cm³ of 0.150 mol dm⁻³ solution.

Give me a hint

Convert the volume to dm³ before multiplying by concentration.

Compare my reasoning
  1. 20.0 cm³ = 0.0200 dm³.
  2. n = cV.
  3. Keep three significant figures.

n(Fe²⁺) = 0.150 × 0.0200 = 3.00 × 10⁻³ mol.

Look for these in your work

  • Volume converted
  • Concentration relation used
  • Precision appropriate
2 · Independent

Use the balanced Fe²⁺ equation to find moles of MnO₄⁻ needed for 3.00 × 10⁻³ mol Fe²⁺.

Give me a hint

Apply the 1:5 mole ratio.

Compare my reasoning
  1. Divide Fe²⁺ moles by five.
  2. State the permanganate amount.
  3. Check the result is smaller than the Fe²⁺ amount.

n(MnO₄⁻) = 6.00 × 10⁻⁴ mol.

Look for these in your work

  • Ratio used in correct direction
  • Moles calculated
  • Magnitude check
3 · Transfer

For the ethanedioate equation, 10.0 cm³ of 0.0250 mol dm⁻³ C₂O₄²⁻ reacts with excess acidified MnO₄⁻. Find the required moles of MnO₄⁻.

Give me a hint

Find oxalate moles, then use 2:5 MnO₄⁻:C₂O₄²⁻.

Compare my reasoning
  1. Convert 10.0 cm³ to 0.0100 dm³.
  2. Find n(C₂O₄²⁻) = 2.50 × 10⁻⁴ mol.
  3. Multiply by 2/5.

n(MnO₄⁻) = 1.00 × 10⁻⁴ mol.

Look for these in your work

  • Volume conversion correct
  • Oxalate moles correct
  • Stoichiometric ratio applied

Common mistakes

  • Forgetting the eight H⁺ in the iron(II) reaction
  • Using a 1:1 ratio for MnO₄⁻ and Fe²⁺
  • Confusing the oxalate and iron(II) mole ratios
  • Using cm³ as dm³ without converting
Recall without your notes

What can you explain now?

In acidified permanganate/Fe²⁺, what is the mole ratio MnO₄⁻:Fe²⁺?

Compare with the explanation

1:5

One permanganate ion accepts five electrons supplied by five Fe²⁺ ions.

After trying it yourself, choose your next review. This is your self-assessment.

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Make it stick

What are the products and mole ratios for acidic permanganate with Fe²⁺ and ethanedioate?

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Course scope and assessment

Four hundred and forty-two original lessons map the published learning outcomes across AS Chemistry Topics 1–22 and A Level Topics 23–37, with guided, independent and transfer practice and explained answers. Every numbered subject-content topic and listed outcome tag now has a mapped lesson sequence. Topic 32 maps all 12 hydroxy-compound outcome tags in 11 lessons; Topic 33 maps all 15 carboxylic-acid and derivative outcome tags in 16 lessons; Topic 34 maps all 22 nitrogen-compound outcome tags in 20 lessons; Topic 35 maps all 12 polymerisation outcome tags in 16 lessons; Topic 36 maps all four organic-synthesis outcome tags in 14 lessons; Topic 37 maps all 22 chromatography and NMR outcome tags in 18 lessons. Cambridge's 2028–2030 Version 1 syllabus states that there are no significant changes which affect teaching from the preceding edition; the routes are aligned to that edition. This is 37 of the 37 numbered subject-content topics. Full cumulative exam assessment, Paper 3 laboratory competence, Paper 5 investigation practice and human subject-teacher review remain outstanding. Written practice is self-checked and does not certify exam readiness.

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