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A Level · Cambridge (CIE) · 9701

Compare halogens as oxidising agents

Rank halogen oxidising strength and use displacement equations to predict reactions with halide ions.

Group 17: the halogens · Cambridge 9701 AS Chemistry · 11.2

AS Level; Cambridge International Chemistry 9701, 2025–2027 syllabus. State conditions for halogen reactions, distinguish halogen oxidising strength from halide-ion reducing strength, and balance redox equations. Chlorine, bromine, iodine and concentrated acids are hazardous; examples teach chemistry, not practical instructions. Written practice is self-checked

Before you begin

  • Use molecular halogen formulas X₂, oxidation numbers, ionic equations and electron-transfer ideas.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

What happens to a halogen molecule when it acts as an oxidising agent?

What you will learn

  • Rank F₂, Cl₂, Br₂ and I₂ as oxidising agents
  • Predict halogen–halide displacement
  • Write balanced ionic equations
Starting halide ionAdded elementCl⁻Br⁻I⁻Cl₂NoYesYesBr₂NoNoYesI₂NoNoNoYes: parent halogen is displaced
Halogen displacement predictions for the stated aqueous model. Columns are starting chloride, bromide and iodide ions. Rows are added chlorine, bromine and iodine elements. Chlorine displaces bromine and iodine; bromine displaces iodine; iodine displaces neither. No displacement is shown with the same halogen's own halide. Yes means the parent halogen is displaced from its halide; No means no displacement in this model, not that every possible reaction in an unspecified mixture is absent.

Halogens gain electrons and act as oxidising agents

A halogen molecule accepts electrons to form halide ions: X₂ + 2e⁻ → 2X⁻. A stronger oxidising agent is more readily reduced and oxidises another species.

Oxidising strength decreases down the group: F₂ > Cl₂ > Br₂ > I₂. Thus chlorine can oxidise bromide or iodide ions, bromine can oxidise iodide ions, and iodine cannot displace chloride or bromide in the standard aqueous comparison.

Use a displacement rule and an ionic equation

A more reactive halogen X₂ displaces a less reactive halogen Y₂ from Y⁻: X₂ + 2Y⁻ → 2X⁻ + Y₂. Check that the oxidising halogen is the one gaining electrons.

Keep oxidising strength of X₂ separate from reducing strength of X⁻. The direction reverses when you compare halide ions as reducing agents.

Pause and explain

Which is the stronger oxidising agent, bromine or iodine?

Put the idea to work

Worked example

Predict and balance the reaction of chlorine with aqueous iodide ions.

Show the worked solution
  1. Chlorine is a stronger oxidising agent than iodine.
  2. Cl₂ gains electrons and I⁻ loses electrons.
  3. Two iodide ions are needed for each Cl₂ molecule.

Answer Cl₂ + 2I⁻ → 2Cl⁻ + I₂.

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

Write the ionic equation for bromine displacing iodide ions.

Give me a hint

Bromine gains two electrons; two I⁻ ions form one I₂ molecule.

Compare my reasoning
  1. Br₂ is the stronger oxidising agent than I₂.
  2. Two I⁻ ions lose two electrons to form I₂.
  3. The products are 2Br⁻ and I₂.

Br₂ + 2I⁻ → 2Br⁻ + I₂.

Look for these in your work

  • Reactants selected
  • Coefficients balanced
  • Electron-transfer direction correct
2 · Independent

Predict whether iodine displaces bromide from aqueous bromide. Explain using oxidising strength.

Give me a hint

The added halogen must be a stronger oxidising agent than the halide's parent halogen.

Compare my reasoning
  1. I₂ is a weaker oxidising agent than Br₂.
  2. I₂ cannot oxidise Br⁻ to Br₂ in the standard series.
  3. No displacement is predicted.

No reaction is predicted: I₂ is a weaker oxidising agent than Br₂ and cannot oxidise Br⁻ to Br₂.

Look for these in your work

  • Outcome correct
  • Relative order stated
  • Reason linked to electron acceptance
3 · Transfer

A solution becomes brown when chlorine is added to an initially colorless iodide solution. Identify the halogen formed and explain the evidence limit.

Give me a hint

Chlorine oxidises iodide to iodine, which is brown in aqueous solution.

Compare my reasoning
  1. Cl₂ displaces iodine from I⁻.
  2. I₂ causes the brown color.
  3. Color supports iodine formation but a full identification should consider controls and other evidence.

Iodine is formed: Cl₂ + 2I⁻ → 2Cl⁻ + I₂. The brown color is consistent with I₂ but color alone is not unique proof in an uncontrolled mixture.

Look for these in your work

  • Species identified
  • Equation supplied
  • Observation qualified

Common mistakes

  • Calling the halide ion the oxidising agent when it loses electrons
  • Reversing the displacement trend
  • Forgetting the coefficient 2 on halide ions
  • Assuming iodine displaces chloride ions
Recall without your notes

What can you explain now?

What happens to a halogen molecule when it acts as an oxidising agent?

Compare with the explanation

It gains electrons

The halogen is reduced to halide ions.

After trying it yourself, choose your next review. This is your self-assessment.

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Make it stick

How does oxidising strength change down Group 17, and how does that predict displacement?

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Chemistry

Course scope and assessment

Four hundred and forty-two original lessons map the published learning outcomes across AS Chemistry Topics 1–22 and A Level Topics 23–37, with guided, independent and transfer practice and explained answers. Every numbered subject-content topic and listed outcome tag now has a mapped lesson sequence. Topic 32 maps all 12 hydroxy-compound outcome tags in 11 lessons; Topic 33 maps all 15 carboxylic-acid and derivative outcome tags in 16 lessons; Topic 34 maps all 22 nitrogen-compound outcome tags in 20 lessons; Topic 35 maps all 12 polymerisation outcome tags in 16 lessons; Topic 36 maps all four organic-synthesis outcome tags in 14 lessons; Topic 37 maps all 22 chromatography and NMR outcome tags in 18 lessons. Cambridge's 2028–2030 Version 1 syllabus states that there are no significant changes which affect teaching from the preceding edition; the routes are aligned to that edition. This is 37 of the 37 numbered subject-content topics. Full cumulative exam assessment, Paper 3 laboratory competence, Paper 5 investigation practice and human subject-teacher review remain outstanding. Written practice is self-checked and does not certify exam readiness.

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