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A Level · Cambridge (CIE) · 9701

Deduce possible structural and stereoisomers from a formula

Generate valid isomer candidates by preserving formula, valency and functional-group possibilities.

An introduction to AS Level organic chemistry · Cambridge 9701 · 13.4

AS Level; Cambridge International Chemistry 9701, 2025–2027 syllabus. Use the published functional-group scope and nomenclature limits; draw formula and mechanism evidence with correct connectivity, electron movement and stereochemistry. Written practice is self-checked

Before you begin

  • Use covalent structures, valency, molecular formulas, lone pairs, and single, double and triple bonds.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

What must every proposed isomer preserve?

What you will learn

  • Enumerate chain and positional alternatives
  • Check functional-group isomers
  • Avoid duplicates and invalid valencies

Begin with a formula and degree of unsaturation

List possible carbon skeletons and functional groups consistent with the formula. Keep the total number of each atom unchanged and use normal valencies.

For simple acyclic formulas containing C, H and a single O, compare alcohol and ether possibilities when the hydrogen count allows them. For a formula with C=C, consider positional isomers and any permitted geometrical forms.

Check identity before counting

Two drawings that differ only by rotating a single bond are not different structural isomers. Two names for the same connectivity are duplicates.

After generating candidates, check each molecular formula, functional group and connectivity. If stereoisomers are requested, count distinct geometrical or optical arrangements only when their structural conditions are satisfied.

Pause and explain

How many chain isomers are there for C₄H₁₀?

Put the idea to work

Worked example

Give the two structural isomers of C₄H₁₀ and identify their isomerism type.

Show the worked solution
  1. Use a four-carbon straight chain: CH₃CH₂CH₂CH₃.
  2. Use a three-carbon parent with one methyl branch: (CH₃)₃CH.
  3. Both have C₄H₁₀ but different carbon skeletons.

Answer Butane and 2-methylpropane are the two chain isomers of C₄H₁₀.

Try a topic test

Choose Easy, Normal or Difficult. Save your answers and open worked review after finishing.

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

Give the structural isomers of C₃H₈O and classify one functional-group pair.

Give me a hint

Consider alcohol positions and an ether connectivity.

Compare my reasoning
  1. CH₃CH₂CH₂OH is propan-1-ol.
  2. CH₃CH(OH)CH₃ is propan-2-ol.
  3. CH₃OCH₂CH₃ is methoxyethane; the ether is a functional-group isomer of the alcohols.

The three structures are propan-1-ol, propan-2-ol and methoxyethane; the alcohols and ether are functional-group isomers.

Look for these in your work

  • All candidates valid
  • Formula conserved
  • Functional types distinguished
2 · Independent

How many positional isomers of butene have the same straight-chain skeleton?

Give me a hint

Move the double bond without redrawing duplicates from the opposite end.

Compare my reasoning
  1. A terminal double bond gives but-1-ene.
  2. An internal double bond gives but-2-ene.
  3. A double bond at carbon 3 is the same as but-1-ene when numbered from the nearer end.

Two: but-1-ene and but-2-ene.

Look for these in your work

  • End position
  • Internal position
  • Duplicate removed
3 · Transfer

A proposed isomer list for C₄H₁₀ includes CH₃CH₂CH₂CH₂CH₃. Diagnose the error.

Give me a hint

Count carbon atoms before comparing structures.

Compare my reasoning
  1. The proposed structure contains five carbon atoms.
  2. C₄H₁₀ allows only four carbon atoms.
  3. The structure is pentane, C₅H₁₂, and must be rejected.

It has five carbons and formula C₅H₁₂, so it is not an isomer of C₄H₁₀.

Look for these in your work

  • Carbon count
  • Formula mismatch
  • Candidate rejected

Common mistakes

  • Changing the formula when branching a structure
  • Counting conformations as structural isomers
  • Listing an invalid carbon valency or duplicated structure
Recall without your notes

What can you explain now?

What must every proposed isomer preserve?

Compare with the explanation

The given molecular formula

Isomers must have the same molecular formula.

After trying it yourself, choose your next review. This is your self-assessment.

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Make it stick

What checks should you make before accepting an isomer as valid?

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Chemistry

Course scope and assessment

Four hundred and forty-two original lessons map the published learning outcomes across AS Chemistry Topics 1–22 and A Level Topics 23–37, with guided, independent and transfer practice and explained answers. Every numbered subject-content topic and listed outcome tag now has a mapped lesson sequence. Topic 32 maps all 12 hydroxy-compound outcome tags in 11 lessons; Topic 33 maps all 15 carboxylic-acid and derivative outcome tags in 16 lessons; Topic 34 maps all 22 nitrogen-compound outcome tags in 20 lessons; Topic 35 maps all 12 polymerisation outcome tags in 16 lessons; Topic 36 maps all four organic-synthesis outcome tags in 14 lessons; Topic 37 maps all 22 chromatography and NMR outcome tags in 18 lessons. Cambridge's 2028–2030 Version 1 syllabus states that there are no significant changes which affect teaching from the preceding edition; the routes are aligned to that edition. This is 37 of the 37 numbered subject-content topics. Full cumulative exam assessment, Paper 3 laboratory competence, Paper 5 investigation practice and human subject-teacher review remain outstanding. Written practice is self-checked and does not certify exam readiness.

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