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A Level · Cambridge (CIE) · 9701

Prepare an alkene by eliminating hydrogen halide

Use ethanolic sodium hydroxide and heat to eliminate HX from a halogenoalkane and form an alkene.

Hydrocarbons · Cambridge 9701 AS Chemistry · 14.2

AS Level; Cambridge International Chemistry 9701, 2025–2027 syllabus. Apply the stated reagents and conditions, balance equations, and keep mechanistic claims within the named examples. Written practice is self-checked

Before you begin

  • Use displayed and structural formulas, covalent bond polarity, balanced equations, and the organic reaction terms from Topic 13.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

Which conditions favor elimination from a halogenoalkane to form an alkene?

What you will learn

  • Recognise elimination as an alkene preparation
  • Select ethanolic NaOH and heat
  • Write a balanced example using bromoethane

Elimination forms a carbon–carbon double bond

When a halogenoalkane is heated with ethanolic sodium hydroxide, H and X are removed from adjacent carbon atoms. A C=C bond forms between them.

For bromoethane, CH₃CH₂Br + NaOH → CH₂=CH₂ + NaBr + H₂O. The ethanol is the solvent and heat is supplied. Aqueous hydroxide instead favors substitution to an alcohol in the syllabus examples.

Distinguish substitution and elimination conditions

Elimination removes atoms or groups to make a multiple bond; substitution replaces the leaving group with another group.

Check both reagent medium and product. If the question specifies ethanolic NaOH and heat, predict the alkene route rather than the aqueous substitution route.

Pause and explain

What happens to the carbon skeleton in elimination of HX?

Put the idea to work

Worked example

Write the equation and conditions for preparing ethene from bromoethane.

Show the worked solution
  1. Remove H from one carbon and Br from its neighbor.
  2. Form C=C between the two carbon atoms.
  3. Add the sodium and displaced hydrogen/bromine products.

Answer CH₃CH₂Br + NaOH → CH₂=CH₂ + NaBr + H₂O; ethanolic NaOH, heat.

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

Write the elimination equation for 2-bromopropane using ethanolic NaOH.

Give me a hint

Remove H and Br from neighboring carbons and show a propene product.

Compare my reasoning
  1. The three-carbon skeleton is retained.
  2. A C=C forms between adjacent carbons.
  3. Balance sodium, bromine, oxygen and hydrogen.

CH₃CHBrCH₃ + NaOH → CH₃CH=CH₂ + NaBr + H₂O (ethanol, heat).

Look for these in your work

  • Three-carbon chain retained
  • Alkene formed
  • Equation balanced
2 · Independent

Choose between ethanolic and aqueous NaOH to make ethene from bromoethane; justify.

Give me a hint

Use the target product and the reaction type.

Compare my reasoning
  1. The target has a C=C bond.
  2. Removal of HBr is elimination.
  3. Ethanolic NaOH with heat favors this syllabus route.

Use ethanolic NaOH and heat to eliminate HBr and form ethene.

Look for these in your work

  • Alkene target recognised
  • Elimination named
  • Conditions selected
3 · Transfer

A learner writes bromoethane + NaOH(aq) → ethene. Explain the mismatch.

Give me a hint

Compare the stated solvent with the intended pathway.

Compare my reasoning
  1. Aqueous hydroxide favors nucleophilic substitution in the syllabus examples.
  2. Substitution replaces Br with OH and forms ethanol.
  3. Use ethanolic NaOH and heat for alkene elimination.

The aqueous conditions favor substitution to ethanol; ethanolic NaOH and heat are used for elimination to ethene.

Look for these in your work

  • Aqueous route identified
  • Substitution product stated
  • Elimination conditions supplied

Common mistakes

  • Using aqueous NaOH for the elimination example
  • Keeping the C–Br bond and also forming C=C
  • Omitting water or sodium halide from the equation
Recall without your notes

What can you explain now?

Which conditions favor elimination from a halogenoalkane to form an alkene?

Compare with the explanation

Ethanolic NaOH and heat

The alcohol solvent and heat are the stated elimination conditions.

After trying it yourself, choose your next review. This is your self-assessment.

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Make it stick

How do the solvent and product distinguish elimination from substitution of a halogenoalkane?

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Chemistry

Course scope and assessment

Four hundred and forty-two original lessons map the published learning outcomes across AS Chemistry Topics 1–22 and A Level Topics 23–37, with guided, independent and transfer practice and explained answers. Every numbered subject-content topic and listed outcome tag now has a mapped lesson sequence. Topic 32 maps all 12 hydroxy-compound outcome tags in 11 lessons; Topic 33 maps all 15 carboxylic-acid and derivative outcome tags in 16 lessons; Topic 34 maps all 22 nitrogen-compound outcome tags in 20 lessons; Topic 35 maps all 12 polymerisation outcome tags in 16 lessons; Topic 36 maps all four organic-synthesis outcome tags in 14 lessons; Topic 37 maps all 22 chromatography and NMR outcome tags in 18 lessons. Cambridge's 2028–2030 Version 1 syllabus states that there are no significant changes which affect teaching from the preceding edition; the routes are aligned to that edition. This is 37 of the 37 numbered subject-content topics. Full cumulative exam assessment, Paper 3 laboratory competence, Paper 5 investigation practice and human subject-teacher review remain outstanding. Written practice is self-checked and does not certify exam readiness.

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