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A Level · Cambridge (CIE) · 9701

Write the free-radical substitution mechanism

Track initiation, propagation and termination in ethane halogenation with single-electron movement.

Hydrocarbons · Cambridge 9701 AS Chemistry · 14.1

AS Level; Cambridge International Chemistry 9701, 2025–2027 syllabus. Apply the stated reagents and conditions, balance equations, and keep mechanistic claims within the named examples. Written practice is self-checked

Before you begin

  • Use displayed and structural formulas, covalent bond polarity, balanced equations, and the organic reaction terms from Topic 13.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

What is formed when Cl₂ undergoes homolytic fission?

What you will learn

  • Write homolytic initiation
  • Identify both propagation steps
  • Recognise radical termination
Ethane chlorination · radical chainInitiationCl₂ → 2Cl• · UVPropagation 1Cl• + C₂H₆ → HCl + C₂H₅•Propagation 2C₂H₅• + Cl₂ → C₂H₅Cl + Cl•Cl• is regeneratedTermination · radicals combineCl• + Cl• → Cl₂ · no radical remainsFish-hook arrows track one electron; equations show one chain example
Ethane halogenation chain: ultraviolet light initiates Cl₂ homolysis to two Cl radicals. Propagation transfers the radical from Cl to ethyl and back to Cl. Termination combines two radicals so none remains. Equations are representative; mixtures can contain further substitution products.

Initiation makes radicals

Ultraviolet light causes homolytic fission of a halogen molecule: Cl₂ → 2Cl•. Each atom receives one electron from the shared pair and becomes a radical.

Single-headed (fish-hook) arrows show movement of one electron. Do not use a full curly arrow for one-electron radical movement.

Propagation carries the chain

For ethane chlorination, Cl• + C₂H₆ → HCl + C₂H₅•, then C₂H₅• + Cl₂ → C₂H₅Cl + Cl•. Each propagation step consumes one radical and produces another, allowing the chain to continue.

Termination occurs when two radicals combine, for example Cl• + Cl• → Cl₂ or C₂H₅• + Cl• → C₂H₅Cl. A termination step removes radical carriers rather than regenerating one.

Pause and explain

What makes a step a propagation step?

Put the idea to work

Worked example

Classify each step in ethane chlorination: Cl₂ → 2Cl•; Cl• + C₂H₆ → HCl + C₂H₅•; C₂H₅• + Cl₂ → C₂H₅Cl + Cl•; Cl• + Cl• → Cl₂.

Show the worked solution
  1. Homolytic halogen splitting forms radicals: initiation.
  2. A radical reacts and another radical forms: propagation.
  3. The second chain step regenerates Cl•: propagation.
  4. Two radicals combine with none left: termination.

Answer The steps are initiation, propagation, propagation and termination.

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

Write the two propagation equations for ethane chlorination.

Give me a hint

First abstract H; then transfer the radical to chlorine.

Compare my reasoning
  1. Cl• removes H from C₂H₆, forming HCl and C₂H₅•.
  2. C₂H₅• reacts with Cl₂.
  3. The products are C₂H₅Cl and Cl•.

Cl• + C₂H₆ → HCl + C₂H₅•; C₂H₅• + Cl₂ → C₂H₅Cl + Cl•.

Look for these in your work

  • First equation balanced
  • Second equation balanced
  • Chain radical regenerated
2 · Independent

Classify C₂H₅• + C₂H₅• → C₄H₁₀.

Give me a hint

Count radical species before and after the step.

Compare my reasoning
  1. Two ethyl radicals react.
  2. The product has no unpaired electron.
  3. No radical remains, so this is termination.

Termination: two ethyl radicals combine to form butane.

Look for these in your work

  • Radicals counted
  • Product described
  • Stage classified
3 · Transfer

A mechanism uses a full curly arrow from Cl–Cl and labels it one-electron fission. Correct the notation.

Give me a hint

Match arrow type to the number of electrons moving.

Compare my reasoning
  1. Homolysis gives one electron to each chlorine atom.
  2. Each movement is a single electron.
  3. Use two single-headed arrows, one from the bond toward each atom.

Use two single-headed (fish-hook) arrows to show the two bonding electrons separating one to each Cl atom.

Look for these in your work

  • Electron split described
  • Correct arrow type named
  • Both directions shown

Common mistakes

  • Calling the first radical-producing step propagation
  • Calling a step termination when a radical is regenerated
  • Using two-electron curly arrows for single-electron movement
Recall without your notes

What can you explain now?

What is formed when Cl₂ undergoes homolytic fission?

Compare with the explanation

Two chlorine radicals

Each chlorine atom takes one electron from the shared pair.

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Make it stick

How can you tell whether a radical-chain step is propagation or termination?

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Chemistry

Course scope and assessment

Four hundred and forty-two original lessons map the published learning outcomes across AS Chemistry Topics 1–22 and A Level Topics 23–37, with guided, independent and transfer practice and explained answers. Every numbered subject-content topic and listed outcome tag now has a mapped lesson sequence. Topic 32 maps all 12 hydroxy-compound outcome tags in 11 lessons; Topic 33 maps all 15 carboxylic-acid and derivative outcome tags in 16 lessons; Topic 34 maps all 22 nitrogen-compound outcome tags in 20 lessons; Topic 35 maps all 12 polymerisation outcome tags in 16 lessons; Topic 36 maps all four organic-synthesis outcome tags in 14 lessons; Topic 37 maps all 22 chromatography and NMR outcome tags in 18 lessons. Cambridge's 2028–2030 Version 1 syllabus states that there are no significant changes which affect teaching from the preceding edition; the routes are aligned to that edition. This is 37 of the 37 numbered subject-content topics. Full cumulative exam assessment, Paper 3 laboratory competence, Paper 5 investigation practice and human subject-teacher review remain outstanding. Written practice is self-checked and does not certify exam readiness.

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