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A Level · Cambridge (CIE) · 9701

Calculate equilibrium constants and amounts

Evaluate Kc or Kp from equilibrium data and use mass balance with a constant expression to determine equilibrium amounts.

Equilibria and acids and bases · Cambridge 9701 AS Chemistry · 7.1

AS Level; Cambridge International Chemistry 9701, 2025–2027 syllabus. Equilibrium constants apply at a fixed temperature; include only gaseous or aqueous species in the relevant expressions. For acid–base work, distinguish strength from concentration. Written practice is self-checked

Before you begin

  • Balance equations, interpret reversible arrows and use concentration in mol dm⁻³.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

Which values belong in an equilibrium-constant calculation?

What you will learn

  • Calculate Kc and Kp from equilibrium data
  • Calculate unknown equilibrium amounts from suitable data
  • Use an expression without requiring quadratic equations

Substitute equilibrium values into the correct expression

First balance the equation, write the K expression, and then substitute concentrations or partial pressures measured at equilibrium. Coefficients become powers before values are entered.

For an unknown equilibrium amount, use the balanced equation and conservation of atoms to express other concentrations in terms of one unknown. Substitute in K and solve using the data provided; this syllabus does not require solving quadratic equations.

Check units and reaction context

Use values for the same temperature and equilibrium mixture. Do not mix initial values with equilibrium values or combine data from different experiments.

Check that the amount calculation respects the reaction stoichiometry and that every concentration is physically possible (non-negative and no larger than the available material permits).

Pause and explain

For A + B ⇌ AB, what is Kc?

Put the idea to work

Worked example

For A(aq) + B(aq) ⇌ AB(aq), equilibrium concentrations are [A]=0.40, [B]=0.40 and [AB]=0.60 mol dm⁻³. Calculate Kc.

Show the worked solution
  1. Kc=[AB]/([A][B]).
  2. Substitute equilibrium values: 0.60/(0.40×0.40).
  3. Evaluate.

Answer Kc = 3.75 dm³ mol⁻¹ under the stated concentration convention.

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

For H₂ + I₂ ⇌ 2HI, equilibrium concentrations are 0.20, 0.10 and 0.60 mol dm⁻³. Calculate Kc.

Give me a hint

Use [HI]²/([H₂][I₂]).

Compare my reasoning
  1. Numerator=0.60²=0.36.
  2. Denominator=0.20×0.10=0.020.
  3. Divide.

Kc=18 dm³ mol⁻¹ under the stated concentration convention.

Look for these in your work

  • Expression correct
  • Values and exponents correct
  • Calculation correct
2 · Independent

For A + B ⇌ AB, an initial 1.00 mol dm⁻³ of each reactant is placed in a vessel; at equilibrium [AB]=0.60 mol dm⁻³. Assuming no product initially, find equilibrium [A], [B] and Kc.

Give me a hint

Use the 1:1:1 stoichiometry to find reactants consumed.

Compare my reasoning
  1. Forming 0.60 mol dm⁻³ AB consumes 0.60 of each reactant.
  2. [A]=[B]=1.00−0.60=0.40 mol dm⁻³.
  3. Kc=0.60/(0.40×0.40).

[A]=[B]=0.40 mol dm⁻³ and Kc=3.75 dm³ mol⁻¹.

Look for these in your work

  • Stoichiometric amount change used
  • Equilibrium reactants found
  • Kc calculated
3 · Transfer

At equilibrium for N₂ + 3H₂ ⇌ 2NH₃, [N₂]=0.20, [H₂]=0.30 and [NH₃]=0.40 mol dm⁻³. Find Kc.

Give me a hint

Apply the powers before multiplication and division.

Compare my reasoning
  1. Kc=[NH₃]²/([N₂][H₂]³).
  2. Numerator=0.16; denominator=0.20×0.027=0.0054.
  3. Divide and retain appropriate precision.

Kc ≈ 29.6 dm⁶ mol⁻² under the stated concentration convention.

Look for these in your work

  • Equation coefficients used as powers
  • Arithmetic correct
  • Concentration-power units consistent

Common mistakes

  • Substituting initial rather than equilibrium amounts
  • Forgetting coefficients as powers
  • Using Kp values in a Kc expression
  • Accepting a negative equilibrium concentration
Recall without your notes

What can you explain now?

Which values belong in an equilibrium-constant calculation?

Compare with the explanation

Equilibrium concentrations or partial pressures

The expression is defined from equilibrium data.

After trying it yourself, choose your next review. This is your self-assessment.

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Make it stick

How do stoichiometric changes and equilibrium data combine to determine unknown amounts?

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Chemistry

Course scope and assessment

Four hundred and forty-two original lessons map the published learning outcomes across AS Chemistry Topics 1–22 and A Level Topics 23–37, with guided, independent and transfer practice and explained answers. Every numbered subject-content topic and listed outcome tag now has a mapped lesson sequence. Topic 32 maps all 12 hydroxy-compound outcome tags in 11 lessons; Topic 33 maps all 15 carboxylic-acid and derivative outcome tags in 16 lessons; Topic 34 maps all 22 nitrogen-compound outcome tags in 20 lessons; Topic 35 maps all 12 polymerisation outcome tags in 16 lessons; Topic 36 maps all four organic-synthesis outcome tags in 14 lessons; Topic 37 maps all 22 chromatography and NMR outcome tags in 18 lessons. Cambridge's 2028–2030 Version 1 syllabus states that there are no significant changes which affect teaching from the preceding edition; the routes are aligned to that edition. This is 37 of the 37 numbered subject-content topics. Full cumulative exam assessment, Paper 3 laboratory competence, Paper 5 investigation practice and human subject-teacher review remain outstanding. Written practice is self-checked and does not certify exam readiness.

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