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A Level · Cambridge (CIE) · 9701

Classify primary, secondary and tertiary halogenoalkanes

Classify the carbon attached to halogen by counting its carbon neighbours.

Halogen compounds · Cambridge 9701 AS Chemistry · 15.1

AS Level; Cambridge International Chemistry 9701, 2025–2027 syllabus. Use the named reagents, solvents, temperatures and pressure conditions; begin curly arrows at a bond or lone pair and distinguish typical mechanisms from absolute rules. Written practice is self-checked

Before you begin

  • Use covalent formulas, nucleophiles, electrophiles, homolytic and heterolytic fission, and the alkene and alcohol pathways in Topics 13–14.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

What determines whether a halogenoalkane is primary, secondary or tertiary?

What you will learn

  • Locate the carbon bonded to X
  • Count its carbon neighbours
  • Distinguish primary, secondary and tertiary structures

Classification depends on the C–X carbon

Find the carbon directly bonded to the halogen X. Count how many other carbon atoms are directly attached to that same carbon.

A primary halogenoalkane has one carbon neighbour at the C–X carbon, a secondary has two, and a tertiary has three. The halogen identity does not set this classification.

Use connectivity rather than the whole molecule

CH₃CH₂Br is primary because the carbon attached to Br is connected to one other carbon. CH₃CHBrCH₃ is secondary; (CH₃)₃CBr is tertiary.

Do not classify from the total number of carbons or from the position of the halogen in the written formula alone. Trace the bonds at the carbon–halogen site.

Pause and explain

What class is CH₃CHBrCH₃?

Put the idea to work

Worked example

Classify CH₃CH₂CHBrCH₃ and (CH₃)₃CCl.

Show the worked solution
  1. For CH₃CH₂CHBrCH₃, inspect the carbon bonded to Br; it has two carbon neighbours.
  2. That halogenoalkane is secondary.
  3. The carbon bonded to Cl in (CH₃)₃CCl has three carbon neighbours, so it is tertiary.

Answer CH₃CH₂CHBrCH₃ is secondary; (CH₃)₃CCl is tertiary.

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

Classify 1-bromobutane and 2-bromobutane.

Give me a hint

Count carbon neighbours of the carbon directly attached to Br.

Compare my reasoning
  1. At C1 of 1-bromobutane, the Br-bearing carbon is attached to one carbon.
  2. At C2 of 2-bromobutane, that carbon is attached to two carbons.
  3. Use the primary/secondary definitions.

1-bromobutane is primary; 2-bromobutane is secondary.

Look for these in your work

  • Correct atom selected
  • Neighbours counted
  • Both labels correct
2 · Independent

A structure has a C–I carbon bonded to three methyl groups. Classify it and explain why iodine does not affect the label.

Give me a hint

Use the carbon connectivity at the C–I site.

Compare my reasoning
  1. The carbon carrying I is attached to three carbon atoms.
  2. That makes the halogenoalkane tertiary.
  3. The identity of I versus Cl or Br does not change the neighbour count.

It is tertiary because the C–I carbon has three carbon neighbours; classification is independent of halogen identity.

Look for these in your work

  • Three neighbours counted
  • Tertiary label stated
  • Halogen role distinguished
3 · Transfer

A learner calls a six-carbon primary halogenoalkane tertiary because the molecule contains many carbons. Correct the method.

Give me a hint

Do not count the whole skeleton; inspect only the carbon bonded to X.

Compare my reasoning
  1. Locate the C–X carbon.
  2. Count the carbons directly attached to that carbon.
  3. Use one, two or three neighbours for primary, secondary or tertiary.

Classify from the number of carbon neighbours at the C–X carbon, not from the molecule's total carbon count.

Look for these in your work

  • Site located
  • Local count used
  • Rule applied

Common mistakes

  • Counting the halogen as a carbon neighbour
  • Classifying by total chain length
  • Calling a halogenoalkane primary because X is on an end of the written formula without checking connectivity
Recall without your notes

What can you explain now?

What determines whether a halogenoalkane is primary, secondary or tertiary?

Compare with the explanation

The number of carbon atoms bonded to the carbon carrying X

Count carbon neighbours at the C–X carbon.

After trying it yourself, choose your next review. This is your self-assessment.

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Make it stick

Which single carbon do you inspect to classify a halogenoalkane, and what do you count?

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Chemistry

Course scope and assessment

Four hundred and forty-two original lessons map the published learning outcomes across AS Chemistry Topics 1–22 and A Level Topics 23–37, with guided, independent and transfer practice and explained answers. Every numbered subject-content topic and listed outcome tag now has a mapped lesson sequence. Topic 32 maps all 12 hydroxy-compound outcome tags in 11 lessons; Topic 33 maps all 15 carboxylic-acid and derivative outcome tags in 16 lessons; Topic 34 maps all 22 nitrogen-compound outcome tags in 20 lessons; Topic 35 maps all 12 polymerisation outcome tags in 16 lessons; Topic 36 maps all four organic-synthesis outcome tags in 14 lessons; Topic 37 maps all 22 chromatography and NMR outcome tags in 18 lessons. Cambridge's 2028–2030 Version 1 syllabus states that there are no significant changes which affect teaching from the preceding edition; the routes are aligned to that edition. This is 37 of the 37 numbered subject-content topics. Full cumulative exam assessment, Paper 3 laboratory competence, Paper 5 investigation practice and human subject-teacher review remain outstanding. Written practice is self-checked and does not certify exam readiness.

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