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A Level · Cambridge (CIE) · 9701

Describe nucleophilic addition to a carbonyl

Show CN⁻ attack at C=O followed by protonation of O⁻ by HCN, regenerating the catalyst.

Carbonyl compounds · Cambridge 9701 AS Chemistry · 17.1

AS Level; Cambridge International Chemistry 9701, 2025–2027 syllabus. Distinguish aldehydes from ketones by structure and evidence; state reagent, condition and observation. Written practice is self-checked

Before you begin

  • Use carbonyl structures, alcohol oxidation and reduction from Topics 13 and 16, nucleophiles and curly arrows, and the organic reaction patterns from Topic 15.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

Where does the cyanide nucleophile attack in carbonyl addition?

What you will learn

  • Start curly arrows at electron pairs
  • Show C=O π-bond movement
  • Explain proton transfer and catalyst regeneration
HCN adds across the carbonyl groupCarbonylR₂C=Opolar C=ONucleophilic attackCN⁻ → carbonyl Cπ pair → Oforms alkoxideProductR₂COH · CNAlkoxide takes H⁺ from HCN → hydroxynitrileCN⁻ is regenerated · KCN is a catalystTrack both curly-arrow electron-pair movements
Nucleophilic addition of HCN to a carbonyl. A cyanide ion donates a lone pair to the electrophilic carbonyl carbon; the C=O pi electrons move to oxygen, forming an alkoxide. The alkoxide takes a proton from HCN to form the hydroxynitrile and regenerate cyanide catalyst. Curly-arrow directions are schematic.

Cyanide attacks the electrophilic carbonyl carbon

CN⁻ donates a lone pair to the δ⁺ carbonyl carbon. At the same time, the C=O π pair moves to oxygen, producing an alkoxide intermediate.

Draw a full curly arrow from a lone pair on carbon in CN⁻ to the carbonyl carbon, and a second arrow from the C=O bond to O. Arrows begin at electrons, not at a positive target.

The alkoxide takes a proton from HCN

The O⁻ intermediate accepts H⁺ from HCN to form the hydroxynitrile. The electrons from the H–C bond return to carbon, regenerating CN⁻ as catalyst.

This is nucleophilic addition: a nucleophile adds to the electrophilic C=O carbon and the π bond opens. KCN supplies CN⁻; HCN supplies the proton and is a reactant.

Pause and explain

Where does the first curly arrow in the mechanism begin?

Put the idea to work

Worked example

Describe the two stages of HCN addition to ethanal.

Show the worked solution
  1. CN⁻ lone pair attacks the carbonyl carbon as the π pair moves to O.
  2. This forms CH₃CH(O⁻)CN.
  3. O⁻ takes H⁺ from HCN to form CH₃CH(OH)CN and regenerate CN⁻.

Answer CN⁻ attacks C=O; the π electrons move to O. The alkoxide then takes H⁺ from HCN, forming 2-hydroxypropanenitrile and regenerating CN⁻.

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

Name both electron-pair movements in the first step of HCN addition to propanone.

Give me a hint

Track the CN⁻ lone pair and the carbonyl π pair.

Compare my reasoning
  1. The CN⁻ lone pair forms a C–C bond to the carbonyl carbon.
  2. The C=O π pair moves to oxygen.
  3. The intermediate is an alkoxide.

CN⁻ lone pair → carbonyl carbon; C=O π pair → O, forming (CH₃)₂C(O⁻)CN.

Look for these in your work

  • First arrow source and target
  • Second arrow source and target
  • Intermediate identified
2 · Independent

What happens to CN⁻ after O⁻ is protonated by HCN?

Give me a hint

Follow the H–C bond electrons during proton transfer.

Compare my reasoning
  1. O⁻ takes H⁺ from HCN.
  2. The H–C bond pair remains with carbon as CN⁻.
  3. The catalyst is regenerated.

CN⁻ is regenerated when the H–C bond pair returns to carbon during proton transfer.

Look for these in your work

  • Proton donor identified
  • Bond-electron path stated
  • Catalyst regenerated
3 · Transfer

A diagram shows CN⁻ attack but no arrow from C=O to O. What charge or intermediate problem results?

Give me a hint

Consider where the π electrons move when the new C–C bond forms.

Compare my reasoning
  1. The carbonyl carbon would exceed its bonding capacity if the π bond stayed unchanged.
  2. The C=O pair must move to oxygen.
  3. That produces O⁻ for the next proton-transfer step.

Move the C=O π pair to O as CN bonds to carbon, giving the alkoxide intermediate.

Look for these in your work

  • Bond capacity checked
  • Arrow corrected
  • Intermediate charge explained

Common mistakes

  • Starting a curly arrow at an atom with no electron pair
  • Leaving the C=O double bond unchanged after CN attack
  • Forgetting the protonation step or catalyst regeneration
Recall without your notes

What can you explain now?

Where does the cyanide nucleophile attack in carbonyl addition?

Compare with the explanation

At the carbonyl carbon

The C=O carbon is electrophilic.

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Make it stick

Why do two nucleophilic-addition steps form a hydroxynitrile and regenerate CN⁻?

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Chemistry

Course scope and assessment

Four hundred and forty-two original lessons map the published learning outcomes across AS Chemistry Topics 1–22 and A Level Topics 23–37, with guided, independent and transfer practice and explained answers. Every numbered subject-content topic and listed outcome tag now has a mapped lesson sequence. Topic 32 maps all 12 hydroxy-compound outcome tags in 11 lessons; Topic 33 maps all 15 carboxylic-acid and derivative outcome tags in 16 lessons; Topic 34 maps all 22 nitrogen-compound outcome tags in 20 lessons; Topic 35 maps all 12 polymerisation outcome tags in 16 lessons; Topic 36 maps all four organic-synthesis outcome tags in 14 lessons; Topic 37 maps all 22 chromatography and NMR outcome tags in 18 lessons. Cambridge's 2028–2030 Version 1 syllabus states that there are no significant changes which affect teaching from the preceding edition; the routes are aligned to that edition. This is 37 of the 37 numbered subject-content topics. Full cumulative exam assessment, Paper 3 laboratory competence, Paper 5 investigation practice and human subject-teacher review remain outstanding. Written practice is self-checked and does not certify exam readiness.

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