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A Level · Cambridge (CIE) · 9701

Write equilibrium expressions in terms of concentration

Construct Kc expressions from balanced equations, using coefficients as powers and omitting pure solids and liquids.

Equilibria and acids and bases · Cambridge 9701 AS Chemistry · 7.1

AS Level; Cambridge International Chemistry 9701, 2025–2027 syllabus. Equilibrium constants apply at a fixed temperature; include only gaseous or aqueous species in the relevant expressions. For acid–base work, distinguish strength from concentration. Written practice is self-checked

Before you begin

  • Balance equations, interpret reversible arrows and use concentration in mol dm⁻³.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

In a Kc expression, what does a balanced-equation coefficient become?

What you will learn

  • Deduce a Kc expression from a balanced equation
  • Use equilibrium concentrations and stoichiometric coefficients
  • Omit pure solids and liquids from the expression

Coefficients become powers in Kc

For aA(aq) + bB(aq) ⇌ cC(aq) + dD(aq), Kc = [C]^c[D]^d / ([A]^a[B]^b), using concentrations at equilibrium.

The coefficient in the balanced equation becomes the power of that species' concentration. A coefficient of one is usually not written as an exponent.

Only relevant aqueous and gaseous concentrations appear

Pure solids and pure liquids are omitted from Kc because their concentrations are effectively constant in this expression. Include aqueous species and gases; use equilibrium, not initial, concentrations.

Kc is tied to a particular balanced reaction and temperature. If the equation is reversed, the expression is inverted; if coefficients are scaled, the powers and constant change accordingly.

Pause and explain

Which species are omitted from Kc?

Put the idea to work

Worked example

Write Kc for N₂(g) + 3H₂(g) ⇌ 2NH₃(g).

Show the worked solution
  1. Place product concentrations in the numerator and reactants in the denominator.
  2. Use coefficient 2 as the power of NH₃ and 3 as the power of H₂.
  3. Use equilibrium concentrations.

Answer Kc = [NH₃]² / ([N₂][H₂]³).

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

Write Kc for H₂(g) + I₂(g) ⇌ 2HI(g).

Give me a hint

Use the coefficient of HI as its exponent.

Compare my reasoning
  1. HI is the product, so it is in the numerator.
  2. H₂ and I₂ are reactants, so they are in the denominator.
  3. Square the HI concentration.

Kc = [HI]² / ([H₂][I₂]).

Look for these in your work

  • Products and reactants placed correctly
  • Coefficient becomes exponent
  • Equilibrium concentrations understood
2 · Independent

Write Kc for CaCO₃(s) ⇌ CaO(s) + CO₂(g).

Give me a hint

Omit the two pure solids.

Compare my reasoning
  1. CaCO₃ and CaO are pure solids.
  2. Only CO₂ remains in the expression.
  3. Use its equilibrium concentration.

Kc = [CO₂].

Look for these in your work

  • Solids omitted
  • Gas included
  • Expression simplified
3 · Transfer

For 2SO₂(g) + O₂(g) ⇌ 2SO₃(g), a student writes Kc = [SO₃]/([SO₂][O₂]). Correct the expression and explain the errors.

Give me a hint

Use products over reactants and preserve each coefficient as a power.

Compare my reasoning
  1. SO₃ coefficient 2 gives [SO₃]².
  2. SO₂ coefficient 2 gives [SO₂]².
  3. O₂ has coefficient one; keep it to the first power.

Kc = [SO₃]² / ([SO₂]²[O₂]). The student omitted coefficient powers for SO₃ and SO₂.

Look for these in your work

  • All coefficients applied
  • Numerator and denominator correct
  • Errors explained

Common mistakes

  • Using coefficients as multipliers instead of powers
  • Putting products in the denominator
  • Including pure solids in Kc
  • Using starting concentrations
Recall without your notes

What can you explain now?

In a Kc expression, what does a balanced-equation coefficient become?

Compare with the explanation

A power on the concentration

Stoichiometric coefficients become exponents.

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Make it stick

How do the balanced equation and physical states determine each term in Kc?

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Chemistry

Course scope and assessment

Four hundred and forty-two original lessons map the published learning outcomes across AS Chemistry Topics 1–22 and A Level Topics 23–37, with guided, independent and transfer practice and explained answers. Every numbered subject-content topic and listed outcome tag now has a mapped lesson sequence. Topic 32 maps all 12 hydroxy-compound outcome tags in 11 lessons; Topic 33 maps all 15 carboxylic-acid and derivative outcome tags in 16 lessons; Topic 34 maps all 22 nitrogen-compound outcome tags in 20 lessons; Topic 35 maps all 12 polymerisation outcome tags in 16 lessons; Topic 36 maps all four organic-synthesis outcome tags in 14 lessons; Topic 37 maps all 22 chromatography and NMR outcome tags in 18 lessons. Cambridge's 2028–2030 Version 1 syllabus states that there are no significant changes which affect teaching from the preceding edition; the routes are aligned to that edition. This is 37 of the 37 numbered subject-content topics. Full cumulative exam assessment, Paper 3 laboratory competence, Paper 5 investigation practice and human subject-teacher review remain outstanding. Written practice is self-checked and does not certify exam readiness.

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