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A Level · Cambridge (CIE) · 9701

Explain molecular polarity and intermolecular forces

Use electronegativity and molecular shape to explain dipoles, London forces, permanent dipoles and hydrogen bonding.

Chemical bonding · Cambridge 9701 AS Chemistry · 3.6

AS Level; Cambridge International Chemistry 9701, 2025–2027 syllabus. Use the supplied Pauling values when given, show particle and bond reasoning, and distinguish intramolecular bonds from intermolecular forces. Written practice is self-checked

Before you begin

  • Read element symbols and simple molecular formulae; use the Periodic Table.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

What two features determine whether a molecule has a net dipole?

What you will learn

  • Explain bond polarity and molecular dipoles
  • Describe instantaneous dipole–induced dipole and permanent dipole–permanent dipole forces
  • Classify hydrogen bonding as a special case

A polar bond does not guarantee a polar molecule

A difference in electronegativity makes the shared electron distribution uneven, giving a bond dipole. A molecular dipole depends on both the bond dipoles and the molecular shape; symmetrical dipoles can cancel.

CO₂ has polar C=O bonds but a linear, symmetrical shape, so the bond dipoles cancel. H₂O is bent, so its O–H bond dipoles do not cancel and the molecule has a dipole.

Van der Waals forces describe intermolecular attractions

In this syllabus, van der Waals' forces is used generically for intermolecular forces. Instantaneous dipole–induced dipole (id-id), or London dispersion, forces arise from temporary uneven electron distributions that induce dipoles in neighbours.

Permanent dipole–permanent dipole (pd-pd) attractions occur between polar molecules. Hydrogen bonding is a special case of pd-pd attraction where hydrogen is bonded to a highly electronegative atom and interacts with a lone pair on a neighbouring molecule.

Pause and explain

Why is CO₂ non-polar overall although each C=O bond is polar?

Put the idea to work

Worked example

Compare molecular dipoles in CO₂ and H₂O.

Show the worked solution
  1. Both have polar bonds because their bonded atoms have different electronegativities.
  2. CO₂ is linear, so its equal C=O dipoles cancel.
  3. H₂O is bent, so its O–H dipoles do not cancel.

Answer CO₂ has no overall dipole because its linear bond dipoles cancel. H₂O has a molecular dipole because its bent shape prevents cancellation.

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

Explain why H₂O has a molecular dipole while CO₂ does not, despite polar bonds in both.

Give me a hint

Compare the molecular geometries before adding the bond dipoles.

Compare my reasoning
  1. H₂O is bent, so its O–H dipoles do not cancel.
  2. CO₂ is linear with equal C=O dipoles in opposite directions.
  3. The resulting dipoles are non-zero for H₂O and cancel for CO₂.

H₂O has a net dipole because its bent shape prevents O–H dipoles cancelling. CO₂ is linear and symmetrical, so its equal C=O dipoles cancel.

Look for these in your work

  • Both bond polarities recognised
  • Shapes compared
  • Net dipole conclusion correct
2 · Independent

Distinguish instantaneous dipole–induced dipole forces from permanent dipole–permanent dipole forces.

Give me a hint

Ask whether the interacting dipoles are temporary or permanent.

Compare my reasoning
  1. A temporary electron fluctuation creates an instantaneous dipole.
  2. It can induce a dipole in a neighbouring particle: id-id.
  3. Polar molecules with permanent dipoles can attract by pd-pd forces.

Id-id (London dispersion) forces arise from temporary dipoles inducing neighbours. Pd-pd forces act between molecules with permanent dipoles.

Look for these in your work

  • Temporary origin stated
  • Induction explained
  • Permanent case contrasted
3 · Transfer

Classify hydrogen bonding within the syllabus terminology and explain what makes it a special case.

Give me a hint

State the generic term, the dipole type and the bonded hydrogen condition.

Compare my reasoning
  1. Van der Waals' forces is used as a generic term for intermolecular forces.
  2. Hydrogen bonding is a special case of permanent dipole–permanent dipole attraction.
  3. The H is bonded to a highly electronegative atom and interacts with a neighbouring lone pair.

Hydrogen bonding is a special case of pd-pd intermolecular attraction involving H bonded to a highly electronegative atom and attraction to a lone pair on a neighbouring molecule.

Look for these in your work

  • Generic use of van der Waals' stated
  • pd-pd classification correct
  • Donor and neighbouring lone pair described

Common mistakes

  • Equating polar bonds with a polar molecule
  • Forgetting shape when adding bond dipoles
  • Calling London forces permanent dipole attractions
  • Treating hydrogen bonding as a covalent bond between molecules
Recall without your notes

What can you explain now?

What two features determine whether a molecule has a net dipole?

Compare with the explanation

Its bond dipoles and molecular shape

Shape determines whether the bond dipoles cancel.

After trying it yourself, choose your next review. This is your self-assessment.

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Make it stick

How do bond polarity, molecular geometry and intermolecular dipoles fit together?

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Chemistry

Course scope and assessment

Four hundred and forty-two original lessons map the published learning outcomes across AS Chemistry Topics 1–22 and A Level Topics 23–37, with guided, independent and transfer practice and explained answers. Every numbered subject-content topic and listed outcome tag now has a mapped lesson sequence. Topic 32 maps all 12 hydroxy-compound outcome tags in 11 lessons; Topic 33 maps all 15 carboxylic-acid and derivative outcome tags in 16 lessons; Topic 34 maps all 22 nitrogen-compound outcome tags in 20 lessons; Topic 35 maps all 12 polymerisation outcome tags in 16 lessons; Topic 36 maps all four organic-synthesis outcome tags in 14 lessons; Topic 37 maps all 22 chromatography and NMR outcome tags in 18 lessons. Cambridge's 2028–2030 Version 1 syllabus states that there are no significant changes which affect teaching from the preceding edition; the routes are aligned to that edition. This is 37 of the 37 numbered subject-content topics. Full cumulative exam assessment, Paper 3 laboratory competence, Paper 5 investigation practice and human subject-teacher review remain outstanding. Written practice is self-checked and does not certify exam readiness.

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