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A Level · Cambridge (CIE) · 9701

Identify monomers from polymer sections

Reverse addition polymerisation by locating the backbone repeat and restoring a C=C bond.

Addition polymerisation · Cambridge 9701 AS Chemistry · 20.1

AS Level; Cambridge International Chemistry 9701, syllabus for 2028–2030. The taught examples are addition polymers of alkenes; do not generalise their disposal behaviour to every polymer. Written practice is self-checked

Before you begin

  • Recognise C=C bonds and displayed, structural and repeat-unit formulae from Topics 13–14.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

What feature identifies an alkene monomer after reversing addition polymerisation?

What you will learn

  • Read a polymer backbone segment
  • Restore a C=C between adjacent backbone carbons
  • Identify the monomer and preserve side groups

Work backwards from the chain

Choose two adjacent carbon atoms in the polymer backbone that came from one alkene monomer. Replace the backbone single bond between them with a C=C bond, then remove the two chain-continuation bonds.

Keep any side group attached to the carbon where it appears. For [–CH₂–CH(Cl)–]ₙ, reversing the process gives CH₂=CHCl, chloroethene.

Do not confuse repeat unit with monomer

The repeat unit is the saturated chain segment inside the polymer. The monomer is the alkene with a C=C bond. A section containing more than one kind of repeat can show more than one monomer; identify each distinct repeat and reverse it separately.

This reasoning reconstructs the monomer from connectivity. It does not reveal the total number of monomers in the original polymer sample.

Pause and explain

How do you handle a side group while recovering the monomer?

Put the idea to work

Worked example

Identify the monomer for [–CH₂–CH(CH₃)–]ₙ.

Show the worked solution
  1. Find the two backbone carbons in the repeat.
  2. Restore a double bond between them.
  3. Keep CH₃ on the same carbon.

Answer CH₂=CHCH₃, propene.

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From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

Identify the monomer for [–CH₂–CH(Cl)–]ₙ.

Give me a hint

Restore the double bond and retain chlorine on the substituted carbon.

Compare my reasoning
  1. Select the two-carbon repeat segment.
  2. Replace its C–C single bond with C=C.
  3. Keep Cl attached to carbon 2.

CH₂=CHCl, chloroethene.

Look for these in your work

  • C=C restored
  • Cl retained
  • Correct monomer name
2 · Independent

A polymer section alternates –CH₂–CH₂– and –CH₂–CH(Cl)– units. Which monomers does it indicate?

Give me a hint

Reverse each distinct repeat unit separately.

Compare my reasoning
  1. The unsubstituted repeat reverses to ethene.
  2. The chlorinated repeat reverses to chloroethene.
  3. List both monomers without inferring their ratio beyond the shown section.

Ethene and chloroethene. The section shows both monomer types; it does not establish the composition of the whole sample.

Look for these in your work

  • Both repeat types identified
  • Both double bonds restored
  • Conclusion limited to the shown section
3 · Transfer

A student identifies CH₃CH₂Cl as the monomer for [–CH₂–CH(Cl)–]ₙ. Explain the correction.

Give me a hint

The recovered monomer must contain the C=C bond that opened during polymerisation.

Compare my reasoning
  1. The repeat unit has a two-carbon backbone.
  2. Restore the backbone C–C bond as C=C.
  3. Retain Cl on carbon 2.

The monomer is CH₂=CHCl, chloroethene, because addition polymerisation opens that C=C bond.

Look for these in your work

  • Unsaturation restored
  • Substituent retained
  • Correct monomer distinguished from saturated haloalkane

Common mistakes

  • Leaving the monomer saturated
  • Removing a side group
  • Moving a substituent to the other carbon
  • Inferring polymer chain length from n in a sample diagram
Recall without your notes

What can you explain now?

What feature identifies an alkene monomer after reversing addition polymerisation?

Compare with the explanation

A C=C bond between the former backbone carbons

The monomer's double bond opens to form the polymer backbone.

After trying it yourself, choose your next review. This is your self-assessment.

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Make it stick

Which bonds do you reverse to recover an alkene monomer from its polymer repeat unit?

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Keep learning Chemistry

Course scope and assessment

Four hundred and forty-two original lessons map the published learning outcomes across AS Chemistry Topics 1–22 and A Level Topics 23–37, with guided, independent and transfer practice and explained answers. Every numbered subject-content topic and listed outcome tag now has a mapped lesson sequence. Topic 32 maps all 12 hydroxy-compound outcome tags in 11 lessons; Topic 33 maps all 15 carboxylic-acid and derivative outcome tags in 16 lessons; Topic 34 maps all 22 nitrogen-compound outcome tags in 20 lessons; Topic 35 maps all 12 polymerisation outcome tags in 16 lessons; Topic 36 maps all four organic-synthesis outcome tags in 14 lessons; Topic 37 maps all 22 chromatography and NMR outcome tags in 18 lessons. Cambridge's 2028–2030 Version 1 syllabus states that there are no significant changes which affect teaching from the preceding edition; the routes are aligned to that edition. This is 37 of the 37 numbered subject-content topics. Full cumulative exam assessment, Paper 3 laboratory competence, Paper 5 investigation practice and human subject-teacher review remain outstanding. Written practice is self-checked and does not certify exam readiness.

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